Let →a,→b and →c be non-zero vectors such that (→a×→b)×→c=13|→b||→c|→a. If θ is the acute angle between the vectors →b and →c, then sinθ equals?
A
13
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B
√23
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C
23
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D
2√23
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Solution
The correct option is D2√23 (→a×→b)×→c=13∣∣∣→b∣∣∣∣∣→c∣∣→a−→c(→a×→b)=13∣∣∣→b∣∣∣∣∣→c∣∣→a−[(→c×→b)→a−(→c×→a)→b]=13∣∣∣→b∣∣∣∣∣→c∣∣→a(→c×→a)→b−(→c×→b)→a=13∣∣∣→b∣∣∣∣∣→c∣∣→a−(→c×→b)→a=13∣∣∣→b∣∣∣∣∣→c∣∣→a−∣∣∣→b∣∣∣∣∣→c∣∣→acosθ=13∣∣∣→b∣∣∣∣∣→c∣∣→acosθ=−13sinθ=2√23