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Question

Let a, b and c be non-zero vectots such that (a b) c = 13b|c|a . If θ is the acute angle between the b and c , then sinθ equals

A
23
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B
23
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C
13
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D
223
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Solution

The correct option is D 223
Given,
(a×b)×c=13|b||c|a
(a×b)×c can be written as c(a×b)
C×(a×b)=13|b||c|a
(cb)a+(ca)b=13|b||c|a
(ca)b=[13|b|c+cb]a

given, a and ¯b are not collenear
cb+13|b|c=0 and ca=0
|c||b|cosθ+13b/|c|=0
|b|c(cosθ+13)=0
cosθ=13
Then, sinθ=83=223


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