Let a- b- and c- be three non-coplanar vectors and let p- q- and r- be the vectors defined by p- - b-c-a-b-c- q- - c-a-a-b-c- r- - a-b-a-b-c- Then a- - b- -p- - b- - c- -q- - c- - a- -r- -

The correct option is D 3 ( a⃗ +b⃗ #160;) ·p⃗ =a⃗·p⃗ +b⃗·p⃗ #160; #160; #160; #160; #160; #160; #160; #160; #160; #16 ...

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Addition of Vectors

Let a⃗, b⃗ ...

Question

Let $\to a, \to b$ and $\to c$ be three non-coplanar vectors and let $\to p, \to q$ and $\to r$ be the vectors defined by $\to p = \frac{\to b \times \to c}{[\to a \to b \to c]}, \to q = \frac{\to c \times \to a}{[\to a \to b \to c]}, \to r = \frac{\to a \times \to b}{[\to a \to b \to c]}$ . Then $(\to a + \to b) \cdot \to p + (\to b + \to c) \cdot \to q + (\to c + \to a) \cdot \to r =$

0

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Solution

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Similar questions

\to a, \to b

\to c

[\to a + \to b + \to c \to a + \to b \to a + \to c] = - [\to a \to b \to c]

\to A = (^i +^j)

\to B = (2^i -^j)

\to C

\to A \cdot \to C = \to B \cdot \to C = \to A \cdot \to B

\to a \cdot \to b

\to c

\to a + \to b \cdot \to b + \to c

\to c + \to a

\to A, \to B

\to C

(\to A + \to B + \to C)

[(\to A + \to B) \times (\to A + \to C)]

\to A = 2 \to i + \to k, \to B = \to i + \to j + \to k

\to C = 4 \to i - 3 \to j + 7 \to k

\to R

\to R \times \to B = \to C \times \to B

\to R \cdot \to A = 0

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