Let →a,→b and →c be three non-zero vectors, no two of which are collinear. If the vector →a+2→b is collinear with →c and →b+3→c is collinear with →a, then →a+2→b+6→c is equal to.
A
λ→a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
λ→b
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
λ→c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
→0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D→0 Since, →a+2→b is collinear with →c. ∴→a+2→b=x→c,xϵR and →b+3→c is collinear with →a. ∴→b+3→c=y→a,yϵR ⇒→a+2→b+6→c=(1+2y)→a Also, →a+2→b+6→c=(x+6)→c ∴(x+6)→c=(1+2y)→a ⇒x+6=0 and 1+2y=0 ⇒x=−6 and y=−1/2 ∴→a+2→b+6→c=→0