Let →a,→b and →c be three units vectors such that 3→a+4→b+5→c=0, then which of the following statements is true?
A
→a is parallel to →b
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B
→a is perpendicular to →b
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C
→a is neither parallel nor perpendicular to →b
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D
None of these
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Solution
The correct option is D None of these Given, 3→a+4→b+5→c=0 They are coplanar →a=−53→c−43→b →a.→b=−53→c.→b−43→b.→b=−53→c.→b−43 Since →a.→b cant be equal to 1 So →a cant be parellel to →b →a.→b can be equal to zero but not strictly So, →a cant be strictly perpendicular to →b So, answer is option D.