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Question

Let a,b,c be vectors of length 3,4,5 respectively. Let a be perpendicular to b+c,btoc+a and ctoa+b. Then a+b+c is

A
25
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B
22
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C
105
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D
52
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Solution

The correct option is D 52

a+b+c=(a+b+c)2=a2+b2+c2+2(a.b+b.c+c.a) {Modulus formula for vectors}

a.(b+c)=0,b.(c+a)=0&c.(a+b)=0 [As the given conditions of being perpendicular}

a.b+b.c+c.a=0 {expanding the previous expression and substituting in the first expression}

a+b+c=a2+b2+c2=32+42+52=52


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