Let a- - i- - j- - k-b- - 5i- - 3j- - 3k-c- - 3i- - j- - 2k- If a vector r- is colinear with c- and - r- - - a- - b- then r- equals-

Given that #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; a⃗ #160; =i⃗ #160; + #160;j⃗ #160; k⃗ #160; ...

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How to Find the Inverse of a Function

Let a⃗ = i⃗...

Question

Let $\to a = \to i + \to j - \to k, \to b = 5 \to i - 3 \to j - 3 \to k, \to c = 3 \to i - \to j + 2 \to k$ If a vector $\to r$ is colinear with $\to c$ and $| \to r | = ∣ ∣ \to a + \to b ∣ ∣$ then $\to r$ equals.

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\to r = 3 \to i + 2 \to j - 5 \to k

\to a = 2 \to i - \to j + \to k

\to b = \to i + 3 \to j - 2 \to k

\to c = - 2 \to i + \to j - 3 \to k

\to r = λ \to a + μ \to b + ν \to c

\to A = 2 \to i + \to k, \to B = \to i + \to j + \to k,

\to C = 4 \to i - 3 \to j + 7 \to k

\to R

\to R \times \to B = \to C \times \to B

\to R . \to A = 0

\to a = \to i - 2 \to j - 3 \to k, \to b = 2 \to i + \to j - \to k, \to c = \to i + 3 \to j - 2 \to k

(\to a \times \to b) \times \to c

\to a = \to i + \to j

\to b = 2 \to j - \to k

\to r \times \to a = \to b \times \to a

\to r \times \to b = \to a \times \to b

\frac{\to r}{| \to r |}

\to A = 2 \to i + \to k, \to B = \to i + \to j + \to k

\to C = 4 \to i - 3 \to j + 7 \to k

\to R

\to R \times \to B = \to C \times \to B

\to R \cdot \to A = 0

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