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Question

Let α=a^i+b^j+c^k,β=b^i+c^j+a^k and γ=c^i+a^j+b^k be three coplanar vectors with abc, and v=^i+^j+^k, then v is perpendicular to

A
α
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B
β
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C
γ
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D
All of these
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Solution

The correct options are
A α
B β
C γ
D All of these
μ¯α+λ¯β+k¯γ=¯0
abcbcacabμλk=0
R1R1+R2+R3
(a+b+c)111bcacab μλk=0
a+b+c100bcbabcacbc μλk=¯0
which mean a+b+c=0 as abc
α.V=β.V=γ.V=a+b+c=0

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