Let F- be the force acting on a particle having position vector r- and - be the torque of this force about the origin then-

The correct option is C r⃗.Γ⃗=0 and F⃗.Γ⃗=0 τ⃗ =r⃗×F⃗ This makes τ nbsp; perpendicular to both r⃗ and F⃗ . Hence τ⃗.r⃗ ...

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Byju's Answer

Standard XII

Physics

Physical Quantities

Let F⃗ be t...

Question

Let $\to F$ be the force acting on a particle having position vector $\to r$ and $\to τ$ be the torque of this force about the origin then:

\to r . \to Γ = 0

and

\to F . \to Γ \neq 0

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\to r . \to Γ \neq 0

and

\to F . \to Γ = 0

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\to r . \to Γ \neq 0

and

\to F . \to Γ \neq 0

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\to r . \to Γ = 0

and

\to F . \to Γ = 0

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Solution

The correct option is C $\to r . \to Γ = 0$ and $\to F . \to Γ = 0$
$\to τ = \to r \times \to F$ This makes $τ$ perpendicular to both $\to r$ and $\to F$ . Hence $\to τ . \to r$ and $\to τ . \to F$ both zero.

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Similar questions

Q. If

\to F

be a force acting on a particle having the position vector

\to r

and

\to τ

be the torque of this force about the origin, then,

\to τ . \to F = 0

and

\to r . \to τ = 0

Q. If

\to F

be a force acting on a particle having the position vector

\to r

and

\to τ

be the torque of this force about the origin, then

Q. If

\to F

is the force acting on a particle having position vector

\to r

and

\to τ

be the torque of this force about the origin, then

Q. If

\to F

be a force acting on a particle having the position vector

\to r

and

\to τ

be the torque of this force about the origin, then

Q. Let

\underset{F}{\to}

be a force acting on a particle having position vector

\underset{r}{\to}

. Let

\underset{Γ}{\to}

be the torque of this force about the origin, then
(a)

\vec{r} . \vec{Γ} = 0 and \vec{F} . \vec{Γ} = 0

(b)

\vec{r} . \vec{Γ} = 0 but \vec{F} . \vec{Γ} \neq 0

(c)

\vec{r} . \vec{Γ} \neq 0 but \vec{F} . \vec{Γ} = 0

(d)

\vec{r} . \vec{Γ} \neq 0 and \vec{F} . \vec{Γ} \neq 0

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Let →F be the force acting on a particle having position vector →r and →τ be the torque of this force about the origin then:

The correct option is C →r.→Γ=0 and →F.→Γ=0→τ=→r×→F This makes τ perpendicular to both →r and →F. Hence →τ.→r and →τ.→F both zero.

Let $\to F$ be the force acting on a particle having position vector $\to r$ and $\to τ$ be the torque of this force about the origin then:

The correct option is C $\to r . \to Γ = 0$ and $\to F . \to Γ = 0$
$\to τ = \to r \times \to F$ This makes $τ$ perpendicular to both $\to r$ and $\to F$ . Hence $\to τ . \to r$ and $\to τ . \to F$ both zero.