Let O-A-a- and O-B-b- A vector along one of the bisectors of the angle - AOB is

The correct option is C a⃗ | a⃗ |+b⃗ | b⃗ | Given #160; O⃗A⃗=a⃗ O⃗B⃗=b⃗ Vector along bisector is ÔÂ+ÔB̂ So ÔÂ=a⃗ |a⃗ | #160; ÔB ...

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Every Point on the Bisector of an Angle Is Equidistant from the Sides of the Angle.

Let O⃗A⃗=a⃗...

Question

Let $\to O A = \to a$ and $\to O B = \to b$ . A vector along one of the bisectors of the angle $∠ A O B$ is

\to a + \to b

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\to a - \to b

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\frac{\to a}{| \to a |} + \frac{\to b}{∣ ∣ \to b ∣ ∣}

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None of these

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\frac{{∣ ∣ \to a + \to b ∣ ∣}^{2} - {∣ ∣ \to a - \to b ∣ ∣}^{2}}{{∣ ∣ \to a + \to b ∣ ∣}^{2} + {∣ ∣ \to a - \to b ∣ ∣}^{2}}

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