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Question

Let u, v, w be such that |u| = 1, |v| = 2, |w| = 3 . If the projection v along u is equal to that of w along u and v, w are perpendicular to each other , then |uv+w| equals

A
14
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B
7
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C
2
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D
14
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Solution

The correct option is A 14
Given,
|u|=1 and |v|=2,|w|=3
and, vu=wu

vu=ωu

or, vω=0
Now, |uv+w|
Squaring,|u|2+v|2+|w|22uv2vω
+2uw
1+4+92uv+2uv-0
14
|uv+w|=14
option A=14


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