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Question

Let x1,x2x100 be 100 observations such that 100i=1xi=0, 1i<j100xixj=80000 and mean deviation about their mean be 5. Then their standard deviation is

A
30
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B
30.00
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C
30.0
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Solution

We have, ¯¯¯x=100i=1xi100=0 (100i=1xi=0)
Now, 100i=1|xi¯¯¯x|100=5
100i=1|xi|=500
Squaring on both sides, we get
(100i=1|xi|)2=(500)2
100i=1|xi|2+21i<j100xixj=250000
100i=1|xi|2100=25000021i<j100xixj100
100i=1|xi|2100=250000160000100
100i=1|xi|2100=900
Required standard deviation
=   100i=1|xi¯¯¯x|2100=   100i=1|xi|2100=30

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