Let x1,x2…x100 be 100 observations such that 100∑i=1xi=0,∑1≤i<j≤100∣∣xixj∣∣=80000 and mean deviation about their mean be 5. Then their standard deviation is
A
30
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B
30.00
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C
30.0
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Solution
We have, ¯¯¯x=100∑i=1xi100=0(∵100∑i=1xi=0)
Now, 100∑i=1|xi−¯¯¯x|100=5 ⇒100∑i=1|xi|=500
Squaring on both sides, we get (100∑i=1|xi|)2=(500)2 ⇒100∑i=1|xi|2+2∑1≤i<j≤100∣∣xixj∣∣=250000 ⇒100∑i=1|xi|2100=250000−2∑1≤i<j≤100∣∣xixj∣∣100 ⇒100∑i=1|xi|2100=250000−160000100 ⇒100∑i=1|xi|2100=900 ∴ Required standard deviation =
⎷100∑i=1|xi−¯¯¯x|2100=
⎷100∑i=1|xi|2100=30