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Question

Let X={1,2,3,4,5}. The number of different ordered pairs (Y,Z) that can be formed such that YX,ZX and YZ is empty is:

A
52
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B
35
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C
25
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D
53
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Solution

The correct option is B 35
YX,ZX

Let aX, then

aY,aZ.....(1)

aY,aZ.....(2)

aY,aZ.....(3)

aY,aZ.....(4)

We require YZ=φ

Thus, for a, equation (1),(2) and (3) can satisfy YZ=φ

Therefore,

YZ=φ has 3 options.

Thus,
No. of required possibilities for 5 elements of X=35

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