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Question

Let x2+αx+β=0 be the equation whose roots are the negatives of the roots of x2+7x2=0, then the value of α+β is

A
5
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B
5
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C
9
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D
9
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Solution

The correct option is D 9
Let x1,x2 be the roots of the equation x2+7x2=0
x1+x2=7, & x1×x2=2
So,
x1,x2 are the roots of the equation
x2+αx+β=0
(x1+x2)=7=αα=7β=(x1)(x2)=x1×x2=2α+β=9

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