CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let X=ABC+BCA+CAB.. Evaluate X for
(a) A = 1, B = 0, C = 1,
(b) A = B = C = 1, and
(c) A = B = C = 0.

Open in App
Solution

Given:
Output X=ABC+BCA+CAB

(a) A = 1, B = 0, C = 1
X=1.(0.1)¯+0.(1.1)¯+1.(1.0)¯ =1.0¯+0.1¯+1.0¯ =1.1+0.0+1.1 =1+0+1 =1+1 =1

(b) A = B = C = 1
X=1.(1.1)¯+1.(1.1)¯+1.(1.1)¯ =1.1¯+1.1¯+1.1¯ =1.0+1.0+1.0 =0+0+0 =0

(c) A = B = C = 0
X=0.(0.0)¯+0(0.0)¯+0.(0.0)¯ =0.0¯+0.0¯+0.0¯ =0.1+0.1+0.1 =0+0+0 =0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Derivative of Simple Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon