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Question

Let x and y are solution of the system of equations {log8(1)+log3(x+2)=log3(32y)2yx23y=0 The value of (yx), is

A
2
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B
5
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C
11
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D
none
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Solution

The correct option is A 2
log18+log(x+2)3=log(32y)3log(x+2)3=log(32y)3x+2=32y2y=32x2y=1x(i)and2(yx)=2(3y)yx=3y2y=3+x(ii)fromequation1&23+x=1xx=1andy=22=1thenyx=1(1)=2

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