Let x be a complex number such that ∣∣∣z−iz+2i∣∣∣ and |z|=52. Then the value of |z+3i| is :
A
√10
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B
72
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C
154
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D
2√3
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Solution
The correct option is B72 If ∣∣∣z−iz+2i∣∣∣=1 and |z|=52 ⇒|z−i|=|z+2i|⇒x2+(y−1)2=x2+(y+2)2⇒y−1=±(y+2)⇒y−1=−y−2⇒y=−12⇒|z|=52⇒x2+y2=254⇒x2+14=254⇒x=±√6|z+3i|=√x2+(y+3)2⇒|z+3i|=72