Let x be a prime number such that x - 23- Given that y-x -1- The number of primes in the list y-1- y-2- y-3 - y-x-1 is-

The correct option is D none of these For 1 ≤ n≤ x 1, y+n = x! + n+1, which is divisible by n+1 always. Therefore, there is no prime number in this list. ...

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Quantitative Aptitude

Divisibility Rule for Composite Numbers

Let x be a pr...

Question

Let x be a prime number such that $x \geq 23$ . Given that y= x!+1. The number of primes in the list y+1, y+2, y+3...y+x-1 is?

x-1

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none of these

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Solution

The correct option is D
none of these

For $1 \leq n \leq x - 1, y + n = x! + n + 1$ , which is divisible by n+1 always.

Therefore, there is no prime number in this list.

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Let x be a prime number such that x≥23. Given that y= x!+1. The number of primes in the list y+1, y+2, y+3...y+x-1 is?

The correct option is D none of these For 1≤n≤x−1, y+n=x!+n+1, which is divisible by n+1 always. Therefore, there is no prime number in this list.

Let x be a prime number such that $x \geq 23$ . Given that y= x!+1. The number of primes in the list y+1, y+2, y+3...y+x-1 is?

The correct option is D
none of these

For $1 \leq n \leq x - 1, y + n = x! + n + 1$ , which is divisible by n+1 always.

Therefore, there is no prime number in this list.