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Question

Let X be a random variable such that the probability function of a distribution is given byP(X=0)=12, P(X=j)=13j (j=1,2,3,,). Then the mean of the distribution and P(X is positive and even) respectively are

A
34 and 19
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B
34 and 116
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C
34 and 18
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D
38 and 18
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Solution

The correct option is C 34 and 18
Mean of distribution (M)
=xiPi
M=0(12)+1(13)+2(132)+3(133)+
M=13+2(132)+3(133)+
M3=132+2(133)+
MM3=13+132+133+
2M3=13232M3=12
Mean =34

P(X is positive and even)
=132+134+136+
=1321132=18

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