Let X be a set having 3 elements and Y be a set having 4 elements. If α is the number of one-one functions from X to Y and β is the number of onto functions from Y to X, then the value of (β−α) is
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Solution
Number of one-one functions :X→Y is n(X)=3=nn(Y)=4=m⇒α=4×3×2=24
Number of onto functions :Y→X is n(Y)=4=mn(X)=3=nβ=nm−(nC1(n−1)m−nC2(n−2)m+…)(∵m>n)⇒β=34−[3C1(2)4−3C2(1)4]⇒β=81−45=36