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Question

Let X be the Poisson random variable with parameter λ=1, then the probability P(0x2) equals

A
12e
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B
32e
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C
52e
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D
72e
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Solution

The correct option is C 52e
Poisson distribution,

P(x)=eλλxx!

λ=1

So,

P(0x2)=P(0)+P(1)+P(2)

=e1(1)00!+e1(1)11!+e1(1)22!

=1e+1e+12e

=52e

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