Question

Let x be the probability of getting a six at least once in four throws of a die and y be the probability of throwing a double six at least once in 24 throws with two dice . Then ,

• A. $x>y$
• B. $x=y$
• C. $x<y$
• D. $x=by$

Answer 1

The correct option is A $x>y$

x= Probability of getting at least one six in four throws =${1-\frac{5}{6}}^4$ = 0.5177
Probability of not getting a double six in one throw with a pair of dice =35/36
Probability of not getting one double six in 24 throws = ${1-\frac{35}{36}}^{24}$ = 0.4914