Let $x = \frac{p}{q}$ be a rational number, such that the prime factorization of $q$ is of the form $2^{n} 5^{m}$ , where $n, m$ are non-negative integers. Then $x$ has a decimal expansion which terminates.

True

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False

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Neither

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Either

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Solution

The correct option is A True
The form of q is $2^{n} * 5^{m}$
q can be $1, 2, 5, 10, 20, 40....$
Any integer divided by these numbers will always give a terminating decimal number.

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Let $x = \frac{p}{q}$ be a rational number, such that the prime factorization of q is not of the form $2^{n} 5^{m}$ , where n, m are non-negative integers. Then, x has a decimal expansion which is ____________.

Let $x = \frac{p}{q}$ be a rational number, such that the prime factorisation of $q$ is not of the form $2^{m} 5^{n}$ , where $n, m$ are non-negative integers. Then, $x$ has a decimal expansion which is

Q. Let

x = \frac{p}{q}

be a rational number, such that the prime factorisation of q is not of the form

2^{m} 5^{n}

, where n, m are non-negative integers. Then, x has a decimal expansion which is:

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Let x=pq be a rational number, such that the prime factorization of q is of the form 2n5m, where n,m are non-negative integers. Then x has a decimal expansion which terminates.

The correct option is A TrueThe form of q is 2n∗5mq can be 1,2,5,10,20,40....Any integer divided by these numbers will always give a terminating decimal number.

Let $x = \frac{p}{q}$ be a rational number, such that the prime factorization of $q$ is of the form $2^{n} 5^{m}$ , where $n, m$ are non-negative integers. Then $x$ has a decimal expansion which terminates.

The correct option is A True
The form of q is $2^{n} * 5^{m}$
q can be $1, 2, 5, 10, 20, 40....$
Any integer divided by these numbers will always give a terminating decimal number.