Let X follows binomial distribution with parameters n,p. If P(X=3)=P(X=5) and p>12, then
5≤n≤7
n≥15
n≥8
3≤n≤7
P(X=3)=P(X=5)⇒(qp)2=nC5nC3
∵qp<1⇒nC5nC3<1⇒(n−3)(n−4)<20 ⇒n<8 and n≥5 ∵n∈N ∴n∈[5,7]
If X follows binomial distribution with parameters n,p with n=5,p(x=2)=9=p(x=3), then p=