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Question

Let x=my+c is normal to x2=4y, if k2+mk+m=0 has only one real value of k,then value(s) of c is/are

A
0
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B
72
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C
72
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D
64
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Solution

The correct option is C 72
Using the slope form of the normal for the given parabola, we get
x=my2mm3
c=2mm3
Now k2+mk+m=0 will have equal roots if
m24m=0m=0,4
Hence values of c=0,72

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