Let x - y- Evaluate - x2-y2x2-2xy-y2-x-yx-y

The correct option is A 1 x^2 y^2x^2+2xy+y^2:x yx+y (x y)(x+y)(x+y)^2×x+yx y =1 ...

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Byju's Answer

Standard IX

Mathematics

Expansion of (a ± b)³

Let x ≠± y....

Question

Let $x \neq \pm y$ . Evaluate :

$\frac{x^{2} - y^{2}}{x^{2} + 2 x y + y^{2}} : \frac{x - y}{x + y}$

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Solution

The correct option is A $1$
$\frac{x^{2} - y^{2}}{x^{2} + 2 x y + y^{2}} : \frac{x - y}{x + y}$

$\frac{(x - y) (x + y)}{(x + y)^{2}} \times \frac{x + y}{x - y}$

$= 1$

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Let x≠±y. Evaluate :x2−y2x2+2xy+y2:x−yx+y

The correct option is A 1x2−y2x2+2xy+y2:x−yx+y(x−y)(x+y)(x+y)2×x+yx−y=1

Let $x \neq \pm y$ . Evaluate :

$\frac{x^{2} - y^{2}}{x^{2} + 2 x y + y^{2}} : \frac{x - y}{x + y}$

The correct option is A $1$
$\frac{x^{2} - y^{2}}{x^{2} + 2 x y + y^{2}} : \frac{x - y}{x + y}$

$\frac{(x - y) (x + y)}{(x + y)^{2}} \times \frac{x + y}{x - y}$

$= 1$