When a coin is tossed 6 times, possible outcomes are,
S={ ( 6T,0H ),( 5T,1H ),( 4T,2H ),( 3T,3H ),( 2T,4H ),( 1T,5H ),( 0T,6H ) }
Here,
T→Tail H→Head
Consider X be the difference between the number of heads and the number of tails
Draw a table for the different sample space:
Outcome | Number of tails | Number of heads | X: difference between number of heads and number of tails |
6T,0H | 6 | 0 | 6−0=6 |
5T,1H | 5 | 1 | 5−1=4 |
4T,2H | 4 | 2 | 4−2=2 |
3T,3H | 3 | 3 | 3−3=0 |
2T,4H | 2 | 4 | 4−2=2 |
1T,5H | 1 | 5 | 5−1=4 |
0T,6H | 0 | 6 | 6−0=6 |
Thus, possible values of X are 0, 2, 4 and 6.