Let [x]= the greatest integer less than or equal to x and let f(x)=sinx+cosx. Then the most general solutions of f(x)=[f(π10)] are
A
2nπ+π2,nϵZ
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B
nπ,nϵZ
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C
2nπ,nϵZ
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D
none of these
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Solution
The correct option is C none of these f(x)=sinx+cosx ⇒f(x)=√2sin(x+π4) Also , given f(x)=[f(π10)] Here, f(π10)=√2sin(7π20) ⇒[f(π10)]=1 ⇒sin(x+π4)=1√2 The general solution is x+π4=nπ+(−1)nπ4 ⇒x=nπ+(−1)nπ4−π4