wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let [x]= the greatest integer less than or equal to x and let f(x)=sinx+cosx. Then the most general solutions of f(x)=[f(π10)] are

A
2nπ+π2,nϵZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
nπ,nϵZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2nπ,nϵZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C none of these
f(x)=sinx+cosx
f(x)=2sin(x+π4)
Also , given f(x)=[f(π10)]
Here,
f(π10)=2sin(7π20)
[f(π10)]=1
sin(x+π4)=12
The general solution is
x+π4=nπ+(1)nπ4
x=nπ+(1)nπ4π4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 7
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon