Question

Let $x,y$ and $z$ be three observations. The mean of these observations is:

• A. $\frac{xyz}{3}$
• B. $\frac{x+y+z}{3}$
• C. $\frac{x-y-z}{3}$
• D. $\frac{xy+z}{3}$

Answer 1

The correct option is B $\frac{x+y+z}{3}$

We know, Mean is given by,

$\text{Mean}=\frac{\text{Sum of the elements}}{\text{Total number of elements}}$.

Given, $x,y,z$ are three observations.

Then, $Mean=\frac{(x+y+z)}{3}$.

Hence, option $B$ is correct.