Let x & y be the real numbers satisfying the equation x2−4x+y2+3=0.If the maximum and minimum values of x2+y2 are M & m respectively , then find the numerical value of (M+m).
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Solution
x2−4x+y2+3=0
⇒x2−4x+4+y2−1=0
(x−2)2+y2=1
represents a circle with center at (2,0)& radius =1 units