Question

Let x.y.z$=$105 where $x,y,z\in N$. Then number of ordered triplets (x, y, z) satisfying the given equation is

• A. 15
• B. 27
• C. 6
• D. 33

Answer 1

The correct option is B 27

$xyz=105=3^1{5}^1{7}^1$

$3^{\prime }$ has $3$ options (i.e whether be in $x,y$ or $z$)

same for $5$ and $7$

$\therefore$ Total number of ways = $3^3=27$