Let x,y,z be positive integers such that HCF(x,y,z)=1 and x2+y2=2z2. Which of the following statements are true? I. 4 divides x or 4 divides y. II. 3 divides x+y or 3 divides x−y. III. 5 divides z(x2−y2).
A
I and II only
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B
II and III only
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C
II only
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D
III only
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Solution
The correct option is C II and III only If H.C.F(x,y,z)=1, then x,y,z are co-prime numbers and given that 2z2 is sum of the squres of 2 co-prime numbers.
Therefore, possible value of z=5⟹2z2=50=492+12
x2+y2=49+1=72+12
Thus, x=7,y=1,z=5 or x=1,y=7,z=5 are possible values.
x−y is divisible by 3 and z(x2−y2) is divisible by 5.