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Question

Let x,y,z be positive real numbers such that x+y+z=12 and x3y4z5=(0.1)(600)3. Then x3+y3+z3 is equal to:

A
258
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B
216
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C
342
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D
270
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Solution

The correct option is C 216
Given,

x+y+z=12

And, x3y4z5=60×600×600

Factorize it

x3y4z5=63×105

=23×33×25×55

=28×33×55

=33×44×55
So, we can say that x=3,y=4 and z=5

Hence, x3+y3+z3=27+64+125=216

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