Let x, y, z be three observations. The mean of these observations is

\frac{x \times y \times z}{3}

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\frac{x + y + z}{3}

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\frac{x - y - z}{3}

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\frac{x \times y + z}{3}

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Solution

The correct option is B $\frac{x + y + z}{3}$
Mean = $\frac{S u m o f a l l o b s e r v a t i o n s}{N u m b e r o f a l l o b s e r v a t i o n s}$

Suggest Corrections

Similar questions

\frac{x \times y \times z}{3}

\frac{x + y + z}{3}

\frac{x - y - z}{3}

\frac{x \times y + z}{3}

3 x (x - y - z) + 3 y (x - y + z) + 3 z (x + y - z)

3 (x + y) (x - y) + 3 z (2 y + z)

x + y + z = 2, 3 x - y + 2 z = 6

3 x + y + z = - 18

∣ ∣ ∣ ∣ \begin{matrix} 3 x & - x + y & - x + z x - y & 3 y & z - y x - z & y - z & 3 z \end{matrix} ∣ ∣ ∣ ∣ = 3 (x + y + z) (x y + y z + x z)

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