Let y=axn,a≠0 has a point of inflection at x=0, then which of the following is correct
A
n∈odd integers
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B
n∈odd integers,n≠1
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C
n∈even integers
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D
n∈even integers,n≠2
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Solution
The correct option is Bn∈odd integers,n≠1 Given curve : y=axn ⇒y′′=n(n−1)axn−2
for point of inflection at x=0: y′′(0+)⋅y′′(0−)<0
only possible if, n−2∈odd integers and n−2≠0 ⇒n∈odd integers
but when n=1,y′′(0+)=y′′(0−)
So, n∈odd integers except one.