Let y -log a k X - z -log a x- Find the relation between y and z-A- z - y - kB- z-k2 yC- z-y - k2D- z - yk

The correct option is D z = yk y = log_akx We can also write this logarithum y = log_10x/log_10a^k = log_10x/klog_10a y = 1/k log_10x/log_10a = 1/klog_a ...

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Byju's Answer

Standard XI

Mathematics

Method of Intervals

Let y =log a ...

Question

Let y = ${log}_{a^{k}} x$ , z = $l o g_{a}$ x. Find the relation between y and z.

z = y/k

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z = yk

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z = k²y

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z = y/k²

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Solution

The correct option is B
z = yk

y = $l o g_{a}$ kx

We can also write this logarithum

y = $\frac{{log}_{10} x}{{log}_{10} a^{k}}$ = $\frac{{log}_{10} x}{k {log}_{10} a}$

y = $\frac{1}{k}$ $\frac{{log}_{10} x}{{log}_{10} a}$ = $\frac{1}{k} {log}_{a} x$

y = $\frac{1}{k}$ . (z) {z = $l o g_{a} x$ }

z = yk

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Similar questions

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Let y = logakx, z = logax. Find the relation between y and z.

The correct option is B z = yk y = logakx We can also write this logarithum y = log10xlog10ak = log10xklog10a y = 1k log10xlog10a = 1klogax y = 1k . (z) {z = logax} z = yk

Let y = ${log}_{a^{k}} x$ , z = $l o g_{a}$ x. Find the relation between y and z.