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Question

Let y=logsin(x2),0<xπ2. The value of dydx at x=π2 is:

A
0
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B
1
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C
π4
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D
π
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Solution

The correct option is D π
y=logsin(x2)
Chain rule leads us to dydx=1sin(x2)×cos(x2)×2x
Substituting x as π2, we get dydx=cotπ4×π=π

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