Question

Let $y=\sec (\frac{\theta }{2}-1)$ then find $\frac{dy}{d\theta }$.

Answer 1

Given,

$y=\sec (\frac{\theta }{2}-1)$

Now differentiating both sides with respect to $\theta$ we get,

$\frac{dy}{d\theta }=\frac{1}{2}\sec (\frac{\theta }{2}-1).\tan (\frac{\theta }{2}-1)$.