wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let z1=2i,z2=2+i. Find Re(z1z2z1)

Open in App
Solution

z1=2i
z2=2+i
z1z2=(2i)(2i)
z1z2=4+2i+2i+1
z1z2=4i3
z1z2z2=(4i32i)(2+i2i)
=8i463i4i2
=5i104+1=i2
Re(i2)=2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon