Let z1and z2be nth roots of unity which are ends of a line segment that subtend a right angle at the origin.Then n must be of the form
A
4k+1
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B
4k+2
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C
4k+3
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D
4k
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Solution
The correct option is D 4k 11n=cos2rπn+isin2rπnLetz1=cos2r1πn+isin2r1πnandz1=cos2r1πn+isin2r1πnThen∠Z1OZ2=amp(z1z2)=amp(z1)−amp(z2)=2(r1−r2)πn=π2(Given)∴n=4(r1−r2)=4×integer,sonisoftheform4k.