Let z1- z2 - C and x - -z1z2- - Rez1z2-1-2-z-2-z1-2 - 1-2-z2- - -z1-2 then

The correct option is B x=0 We know that, |z_ 2 z_ 1 |^ 2 = |z_ 2 | ^ 2 + |z_ 1 | ^ 2 2Re( z̅_̅ ̅2̅ z_ 1 ) nbsp; Given that, x=|z_ 1 z_ 2 | ...

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Properties of Modulus

Let z1, z2 ...

Question

Let $z_{1}, z_{2} \in C$ and $x = | z_{1} z_{2} | - R e (z_{1} z_{2}) - \frac{1}{2} |_{2} - z_{1} |^{2} + \frac{1}{2} (| z_{2} | - | z_{1} |)^{2}$ then

x < 0

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x = 0

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x \geq 1

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0 < x < 1

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Solution

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