CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
49
You visited us 49 times! Enjoying our articles? Unlock Full Access!
Question

Let Z1,Z2C such that Z21+Z22R. If Z1(Z213Z22)=10 and Z2(3Z21Z22)=30, Find the value of (Z21+Z22).

A
Z21+Z22=10
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Z21+Z22=15
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Z21+Z22=20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Z21+Z22=50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Z21+Z22=10
Z313Z!Z22=10 ...(1)
3Z2Z21Z32=30
3Z2Z21iZ32i=Z32i=30i .... (2)
eqn.(1)+(2)=
Z313Z1Z22+3Z2Z21iz32i=10+30i
(Z1+iZ2)3=10+30i
|(Z1+iZ2)3)|=|10+30i|
|Z1+iZ2|3=100+900
(Z21+Z22)3=1000
Z21+Z22=(1000)1/3
Z21+Z22=10

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon