Let z1,z2,z3,z4 are distinct complex numbers representing the vertices of a quadrilateral ABCD taken in order. If z1−z3=z2−z4 and arg(z4−z1z2−z1)=π2, then the quadrilateral is
A
rectangle
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B
rhombus
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C
square
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D
trapezium
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Solution
The correct option is A rectangle
From z1−z2=z3−z4⇒|z1−z2|=|z3−z4|
and arg(z1−z2z3−z4)=0 ∴AB=CD,AB∥CD
Now arg(z4−z1z2−z1)=π2 ⇒AD⊥AB
Hence, ABCD will be rectangle.