Let z be a complex number satisfying equation zp=z−q, where p,qϵN, then
A
If p=q, then number of solutions of equation will be infinite
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B
If p=q, then number of solutions of equation will be finite
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C
If p≠q, then number of solutions of equation will be p+q+1
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D
If p≠q, then number of solutions of equation will be p+q
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Solution
The correct options are A If p=q, then number of solutions of equation will be infinite C If p≠q, then number of solutions of equation will be p+q+1 If p=q, then equation becomes zp=¯¯¯zq and it has infinite number of solutions because any zϵR will satisfy it.