The correct option is C Re(logz)=log(53)
Let z=x+iy
Given z+|z|=3+i
⇒x+iy+√x2+y2=3+i
⇒x+√x2+y2=3 and y=1
⇒x+√x2+1=3
⇒x2+1=(3−x)2⇒x=43
⇒z=43+i
⇒|z|=√169+1=53
∴tanθ=14/3=34 (x>0,y>0,z lies in Q1).
⇒sinθ=35, cosθ=45⇒sin3θ+cos3θ=91125
We know logz=log|z|+i⋅θ , where θ=argz
∴Re(logz)=log|z|=log(53)
z−¯z=(43+i)−(43−i)=2i