CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

Let z be a complex number such that |z|+z=3+i (where i=1). Then |z| is equal to :

A
53
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
54
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
343
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
414
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 53
|z|+z=3+i (1)
Let z=x+iy
|z|=x2+y2
From equation (1)
x2+y2+x+iy=3+i(x2+y2+x)+iy=3+iy=1x2+1+x=3x2+1=3xx2+1=(3x)2x=43

Thus, |z|=x2+y2
=(43)2+(1)2
=53

flag
Suggest Corrections
thumbs-up
61
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Representation and Trigonometric Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon