Let z be a complex number such that |z|=z+32−24i. Then Re(z)+Im(z) is equal to
A
17
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B
31
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C
25
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D
−17
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Solution
The correct option is A17 |z|=z+32−24i⇒z=(|z|−32)+24i⇒|z|2=(|z|−32)2+242⇒|z|2=|z|2−64|z|+322+242⇒64|z|=82(42+32)⇒|z|=25
So, 25=z+32−24i⇒z=−7+24i∴Re(z)+Im(z)=−7+24=17