Question

Let $z$ be a complex such that $-\frac{\pi }{4}\le \arg \left(z\right)\le \frac{\pi }{4}$ and $|z|\le 4$. Then the area enclosed between them is

• A. $8\pi$
• B. $4\pi$
• C. $2\pi$
• D. $12\pi$

Answer 1

The correct option is B $4\pi$


Area $=\frac{1}{4}\times \pi r^2=\frac{1}{4}\times \pi \times 4^2=4\pi$