Let z be those complex number which satisfy |z+5|≤4 and z(1+i)+¯z(1−i)≥−10,i=√−1. If the maximum value of |z+1|2 is α+β√2, then the value of (α+β) is
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Solution
Let z=x+iy
Given, |z+5|≤4 ⇒(x+5)2+y2≤16
Also, z(1+i)+¯z(1−i)≥−10 ⇒x−y≥−5....(2)
From (1) and (2)
Locus of z is the shaded region in the diagram. |z+1| represents distance of 'z' from Q(−1,0)
Clearly 'P' is the required position of 'z' when |z+1| is maximum. ∴P≡(−5−2√2,−2√2) ∴PQ2=32+16√2 ⇒α=32 ⇒β=16
Thus, α+β=48