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Byju's Answer
Standard XII
Mathematics
Modulus of a Complex Number
Let zi, i =...
Question
Let
z
i
,
i
=
1
,
2
,
.
.
.
.6
be the roots of
z
6
+
z
4
=
2
then
6
∑
i
=
1
|
z
i
|
4
is equal to
A
4
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B
6
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C
8
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D
10
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Solution
The correct option is
D
10
Let
z
2
=
t
⇒
t
3
+
t
2
−
2
=
0
⇒
(
t
−
1
)
(
t
2
+
2
t
+
2
)
=
0
⇒
t
=
1
or
t
2
+
2
t
+
2
=
0
⇒
t
=
±
1
or
t
=
1
±
i
⇒
t
=
1
±
i
⇒
|
z
|
2
=
√
2
⇒
|
z
|
4
=
2
⇒
6
∑
i
=
1
|
z
i
|
4
=
1
+
1
+
2
+
2
+
2
+
2
=
10
Suggest Corrections
0
Similar questions
Q.
Let
|
z
i
|
=
i
,
i
=
1
,
2
,
3
,
4
and
|
16
z
1
z
2
z
3
+
9
z
1
z
2
z
4
+
4
z
1
z
3
z
4
+
z
2
z
3
z
4
|
=
48
,
then the value of
∣
∣
∣
1
¯
¯
¯
z
1
+
4
¯
¯
¯
z
2
+
9
¯
¯
¯
z
3
+
16
¯
¯
¯
z
4
∣
∣
∣
.
Q.
Let
z
i
,
¯
¯
¯
z
i
(
i
=
1
,
2
,
.
.
,
5
)
are the complex roots of the equation
x
10
+
(
13
x
−
1
)
10
=
0
,
where the bar denotes complex conjugation. Then the value of
5
∑
i
=
1
1
z
i
¯
¯
¯
z
i
is
Q.
If
i
2
=
−
1
, then
1
+
i
2
+
i
4
+
i
6
+
i
8
+
.
.
.
.
.
.
.
.
.
.
.
.
.
t
o
(
2
n
+
1
)
terms is equal to
Q.
If
i
2
=
−
1
, then
1
+
i
2
+
i
4
+
i
6
+
i
8
+
.
.
.
to (2n+1) terms :
Q.
i
2
=
−
1
, then
i
2
+
i
4
+
i
6
+
i
8
+
.
.
.
+
(
2
n
)
terms is:
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